406=1/2(n^2-n)

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Solution for 406=1/2(n^2-n) equation: 


n in (-oo:+oo)

406 = (1/2)*(n^2-n) // - (1/2)*(n^2-n)

406-((1/2)*(n^2-n)) = 0

(-1/2)*(n^2-n)+406 = 0

406-1/2*(n^2-n) = 0

406-1/2*(n^2-n) = 0

1/2*n-1/2*n^2+406 = 0

1/2*n-1/2*n^2+406 = 0

1/2*n-1/2*n^2+406 = 0

DELTA = (1/2)^2-(-1/2*4*406)

DELTA = 3249/4

DELTA > 0

n = ((3249/4)^(1/2)-1/2)/(-1/2*2) or n = (-(3249/4)^(1/2)-1/2)/(-1/2*2)

n = -28 or n = 29

(n+28)*(n-29) = 0

(n+28)*(n-29) = 0

( n+28 )

n+28 = 0 // - 28

n = -28

( n-29 )

n-29 = 0 // + 29

n = 29

n in { -28, 29 }

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